The temperature at which the kinetic energy of oxygen molecules becomes double than its value at 27 °C is
Text Solution
Verified by ExpertsThe correct answer is:
B
The kinetic energy is given by KE = 
kT.
Let the kinetic energy be K’ at 27 °C and the kinetic energy be K’ at T' temperature. As given in the question, K’ = 2K 1 . Hence,
T’ = 600 K
In Celsius the temperature is T' - 273 = 327 °C
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